Integrand size = 24, antiderivative size = 126 \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {1}{a^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {1}{2 a (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(a+b x) \log (x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(a+b x) \log (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Time = 0.04 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {660, 46} \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {1}{2 a (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {1}{a^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\log (x) (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(a+b x) \log (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rule 46
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b^2 \left (a b+b^2 x\right )\right ) \int \frac {1}{x \left (a b+b^2 x\right )^3} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = \frac {\left (b^2 \left (a b+b^2 x\right )\right ) \int \left (\frac {1}{a^3 b^3 x}-\frac {1}{a b^2 (a+b x)^3}-\frac {1}{a^2 b^2 (a+b x)^2}-\frac {1}{a^3 b^2 (a+b x)}\right ) \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}} \\ & = \frac {1}{a^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {1}{2 a (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(a+b x) \log (x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(a+b x) \log (a+b x)}{a^3 \sqrt {a^2+2 a b x+b^2 x^2}} \\ \end{align*}
Time = 1.03 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.49 \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {a (3 a+2 b x)+2 (a+b x)^2 \log (x)-2 (a+b x)^2 \log (a+b x)}{2 a^3 (a+b x) \sqrt {(a+b x)^2}} \]
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Time = 2.14 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.65
method | result | size |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (\frac {b x}{a^{2}}+\frac {3}{2 a}\right )}{\left (b x +a \right )^{3}}-\frac {\sqrt {\left (b x +a \right )^{2}}\, \ln \left (b x +a \right )}{\left (b x +a \right ) a^{3}}+\frac {\sqrt {\left (b x +a \right )^{2}}\, \ln \left (-x \right )}{\left (b x +a \right ) a^{3}}\) | \(82\) |
default | \(\frac {\left (2 b^{2} \ln \left (x \right ) x^{2}-2 b^{2} \ln \left (b x +a \right ) x^{2}+4 a b \ln \left (x \right ) x -4 \ln \left (b x +a \right ) x a b +2 a^{2} \ln \left (x \right )-2 a^{2} \ln \left (b x +a \right )+2 a b x +3 a^{2}\right ) \left (b x +a \right )}{2 a^{3} \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}\) | \(91\) |
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Time = 0.23 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.63 \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\frac {2 \, a b x + 3 \, a^{2} - 2 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \log \left (b x + a\right ) + 2 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \log \left (x\right )}{2 \, {\left (a^{3} b^{2} x^{2} + 2 \, a^{4} b x + a^{5}\right )}} \]
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\[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\int \frac {1}{x \left (\left (a + b x\right )^{2}\right )^{\frac {3}{2}}}\, dx \]
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Time = 0.20 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.62 \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=-\frac {\left (-1\right )^{2 \, a b x + 2 \, a^{2}} \log \left (\frac {2 \, a b x}{{\left | x \right |}} + \frac {2 \, a^{2}}{{\left | x \right |}}\right )}{a^{3}} + \frac {1}{\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2}} a^{2}} + \frac {1}{2 \, a b^{2} {\left (x + \frac {a}{b}\right )}^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.53 \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=-\frac {\log \left ({\left | b x + a \right |}\right )}{a^{3} \mathrm {sgn}\left (b x + a\right )} + \frac {\log \left ({\left | x \right |}\right )}{a^{3} \mathrm {sgn}\left (b x + a\right )} + \frac {2 \, a b x + 3 \, a^{2}}{2 \, {\left (b x + a\right )}^{2} a^{3} \mathrm {sgn}\left (b x + a\right )} \]
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Timed out. \[ \int \frac {1}{x \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx=\int \frac {1}{x\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{3/2}} \,d x \]
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